What would happen if you did an experiment in which the iodine solution was placed in the dialysis tubing bag and the starch solution was in the beaker? The dialysis tubing is permeable to iodine, but not to starch. Would the color of the water in the beaker at the end of the experiment be orange (brown) or black? Why? Explain your logic.

1 answer

In this experiment, you're dealing with a scenario involving the diffusion of iodine and starch across a semi-permeable membrane (the dialysis tubing).

Here's what happens step by step:

  1. Iodine's Properties: Iodine is a small molecule that can easily pass through the dialysis tubing. It will diffuse from the inside of the dialysis bag (where there is iodine solution) to the outside (the beaker).

  2. Starch's Properties: Starch is a large, complex carbohydrate that cannot pass through the dialysis tubing. Therefore, the starch solution will remain in the beaker and will not enter the dialysis bag.

  3. Color Reaction: When iodine comes into contact with starch, a blue-black color develops due to the formation of a complex between iodine and amylose (a component of starch).

Now, let's analyze the situation:

  • Initially, the starch solution in the beaker is clear or colorless because starch does not react with any free iodine present in the solution.
  • As iodine diffuses out of the dialysis tubing into the beaker, it will mix with the starch.
  • If sufficient iodine enters the beaker to react with the starch, you will observe a color change. The iodine will interact with the starch, resulting in the formation of the blue-black complex.

Given this reasoning, the color of the water in the beaker at the end of the experiment would be blue-black, not orange or brown. The black color results from the starch-Iodine reaction and is due to the presence of both starch and iodine in the solution after diffusion occurs.