What would be the product of a reaction between methanal and pyrrolidine in acid?
I know that normally a reaction between a carbonyl and a secondary amine would form an enamine. Here I am confused because there are no hydrogens that can be removed to form the enamine as this is methanal. I'm guessing that the nitrogen will attack the C=O double bond and then water will be formed as a leaving group, the nitrogen lone pair will come down to form a double bond and push this off. I'm not sure where to go from here as there will be a positive charge on the N.