It will be pKa2.
pH = pKa2 + log[(base)/(acid)]
If base = acid, then log 1 = 0 and pH = pKa2.
What would be the pH of a solution prepared by combining equal quantities of NaH2PO4 and Na2HPO4? Explain with an equation.
4 answers
How do u find pKa2
Look up Ka2, (and Ka1 and Ka3 will be in the same table) for H3PO4.
Then pKa2 = -log(Ka2) = ?
Then pKa2 = -log(Ka2) = ?
ka2=6.2x10^-8
pka2=-log(ka2)=-log(6.2x10^-8)=7.2
pH=7.2
pka2=-log(ka2)=-log(6.2x10^-8)=7.2
pH=7.2
3 answers