NH3 + H2O ==> NH4^+ + OH^-
0.563..........0........0
-x..............x........x
0.563-x.........x........x
Kb = 1.68E-5 = (x)(x)/(.563-x)
Solve for x, which is OH^-, convert to pOH, then to pH. I agree that the answer isn't 4.5
What would be the pH of a 0.563 M solution of ammonia (NH3) at room temperature? The Kb of ammonia is 1.78 × 10−5.
1. 2.5
2. 7
3. 9
4. 4.5
5. 11.5
( I did this problem but apparently 4.5 isnt the answer)
3 answers
i got 11.5 but im not sure because the problems i did before i had to change to ka first and that was the pH and got those answers right...but i don't understand why i have to do it this way though its the right way...quest is saying its wrong..
It's 11.5
1 answer