What would be the new temperature in Celsius of a sample of methane if 205 ml at 725 torr and 75.0 degrees C is allowed to change to 907 ml and 827 torr?
I used P1V1/T1=P2V2/T2
Plugged in the numbers (205)(725)/(348.15K)=(907)(827)/T2
When I solved for T2 I got 1.757*10^3, and I then subtracted 273.15 to get to Celsius.
Am I on the right track?
Please and thanks!
2 answers
Carl, what's with all the names? Jim, Carl, George, Blaine et al. You confuse us when you do this and it makes it much harder to help you.
I didn't check the math but the procedure is correct and I see you converted all of the C to K first. That's good.