What would be the compound amount after 19 years an investment of 42,000 with an 11% interest rate compounded annually?

Answer 1

P = Po*(1+r)^n

r = 11%/100% = 0.11 = APR expressed as a decimal.

n = 1Comp/yr * 19yrs = 19 Compounding
periods.

Plug the above values into the given Eq