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What would be the change in energy for an atom when an electron goes from n=6 to n=3?

I'm assuming it would be negative because you would have to lose energy to go down energy levels. Would that be correct?

1 answer

delta E = 2.180E-18 J*[1/(n1)^2 - 1/(n2)^2]
delta E = 2.180E-18 J*(1/3^2 - 1/6^2)
This is the amount of energy in J that is emitted when an electron moves from the n = 6 to n = 3. By the way this is for a H atom and not just any atom.
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