what would be the answer when you plug 5pi/4 into this equation 6sec^2x-7sinx for x? i cant get the answer need some help

6 answers

With what you are not able to calculate the above?

If you are using a calculator, make sure you know how to set the angle input to radians. By default, most calculators work in degrees.

sec²(x)
=sec²(5π/4)
=1/(-sqrt(2)/2)²
=2
sin(5π/4)
=sqrt(2)/2
So
6sec^2x-7sinx = ?
should read:
sin(5π/4)
=-sqrt(2)/2
what would be the answer?
i don't know what would be the answer
Daniel, this is homework help.

Do I understand that you are not able to calculate
6sec^2x-7sinx
when sec(x)^2 and sin(x) have been calculated for you?
Or is it that the answer that you've got does not match?

Please clarify.
6 sec^2 (5?/4) - 7 sin (5?/4) =
= 6 (1/(-1/sqrt(2)))^2 - 7 (-1/sqrt(2))
= 6 (2) + 7/sqrt(2)
= 12 + 7/sqrt(2)
Similar Questions
    1. answers icon 1 answer
  1. A curve with polar equationr=(8)/7sinx + 36cosx represents a line. This line has a Cartesian equation of the form y=mx+b ,where
    1. answers icon 3 answers
  2. Hi there,Can someone help me with the question: "Prove that the value of 7sinx +3cos2x cannot be greater than 5/1/24 for all
    1. answers icon 4 answers
    1. answers icon 1 answer
more similar questions