The deceleration rate will be
a = F/m = 2 m/s^2. The time to stop is given by
t = Vo/a = (10 m/s)/(2m/s^2) = 5 s
What will the stopping distance be for a 1,000-kg car if -2,000 N of force are applied when the car is traveling 10 m/s?
3 answers
calculate the KE of a 1500 kg. car travelling at 60 km/h
45000j