what will be the focus and directrix of parabola y*y = -16x.

Answer 1

Given: y*y = -16x.

y^2 = -16x,
x = -(1/16)y^2, x-parabola.
a = -(1/16),
4a = -(4/16) = -(1/4),
1/4a = -4.
[1/4a] = 4.
V(h,k), k = Yv = -b/2a = 0/2a = 0.
h = -(1/16)0^2 = 0.

F(X1,0), V(0,0), D(X2,0).

X1 = k - [1/4a] = 0 - 4 = -4.

X2 = k + [1/4a] = 0 + 4 = 4.

F(-4,0), V(0,0), D(4,0).