mols Al2(SO4)3 = grams/molar mass.
molality = mols from above/kg solvent.
delta T = i*Kb*m
You know m, look up Kb, i = 5 for Al2(SO4)3, solve for delta T, then add to 100 for the new boiling point.
what will be the boiling point 54.5 grams of aluminum sulfate dissolved in 805 grams H2O
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