How many moles do you have of CH3OH? That is mols = grams/molar mass = ?
Then M = moles/L soln.
You know M and you know mols, solve for L.
That L will be the total volume; I suppose the author of the problem expects you to subtract the total volume - volume CH3OH in the 36.8 g but there is no density given and the volumes are not additive. Frankly, I don't think that part of the problem can be solved.
What volume of solvent should be added to
36.8 g of CH3OH to produce a 0.500 M solution of CH3OH?
1 answer
1 answer