Where did you get that reaction equation? Atomic O is not stable product
The reaction is actually
2 KBrO3 -> 2 KBr + 3 O2
Calculate the number of KBrO3 moles you start with, using the molar mass; then take 3/2 that number as the number of moles of O2 that form. Call it n.
The use V = n R T/P for the volume V
You need to specify the absolute temperature T and pressure P. At 0 C and 1 atm, each mole occupies 22.4 liters.
I'll be glad to critique your work.
What volume of oxygen gas is produced when 17.5 grams of KBrO3 decomposes?
and the equation is KBrO3==>KBr+30
HELP ME PLZ
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