Asked by Lilian
What volume of hydrogen is produced at s.t.p when 260g of zinc reacts with excess HCl acid.
Answers
Answered by
oobleck
write the equation. Each mole of Zn produces 1 mole of H2
So, how many moles of Zn is 260g ?
If there are n moles, then they will occupy 22.4n L of space.
So, how many moles of Zn is 260g ?
If there are n moles, then they will occupy 22.4n L of space.
Answered by
DrBob222
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = grams/atomic mass = 260/65.38 = approx 4 but that's an estimate only.
Convert mols Zn to mols H2 produced. That's 1:1; therefore, mols Zn = mols H2.
You know 1 mol H2 @ stp occupies 22.4 L so
mols H2 x 22.4 = L H2 @ STP.
mols Zn = grams/atomic mass = 260/65.38 = approx 4 but that's an estimate only.
Convert mols Zn to mols H2 produced. That's 1:1; therefore, mols Zn = mols H2.
You know 1 mol H2 @ stp occupies 22.4 L so
mols H2 x 22.4 = L H2 @ STP.
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