Use the dilution formula of
c1v1 = c2v2
18M*vmL = 6M*250mL
v = ?mL.
what volume of concentrated 18M H2SO4 is required to prepare 250mL of a 6.0M solution?
how would you solve this problem? i know it has something to do with the molarity formula but no idea how to apply it
5 answers
so v would be 83mL?
well, if I had one liter of the final stuff I would have 6 mols of H2SO4 in it
so in 250 mL I need 6/4 or 1.5 mols H2SO4
so the real question is:
What volume of 18M H2SO4 contains 1.5 mols of H2SO4
well there are 18 in a liter
so
I need 1.5/18 liter =.08333...... Liter which is 83 mL
so in 250 mL I need 6/4 or 1.5 mols H2SO4
so the real question is:
What volume of 18M H2SO4 contains 1.5 mols of H2SO4
well there are 18 in a liter
so
I need 1.5/18 liter =.08333...... Liter which is 83 mL
ohh okay now i understand. thank you
You are welcome :)
1 answer