Produce 25.4 g CuCl2 from what? Cu? amd Cl2?
Cu + Cl2 == CuCl2
mols CuCl2 = 25.4 g/molar
mols Cl2 = same as mols Cu.
Then use PV = nRT, substitute mole Cl2 for n, substitute P and T (remember T must be in kelvin) and solve for V in Liters.
what volume of chlorine is required to produce 25.4grams of copper II chloride at 18 degrees celsius and 2.13 atm
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