What volume of carbon tetrachloride (density = 2.71 g/mL) contains 2.46x10^25 chlorine atoms?

Question

I did: 2.46x10^25 Cl atoms x 1 atom/4 atoms x 1 mol/6.02x10^23 x 154 g/1 mol x 1 mL/2.71 g

And the correct answer is apparently 572 mL when I got 581 mL.