MgCO3 ==> MgO + CO2
1 kg MgCO3 = 1000 g.
mols MgCO3 = grams/molar mass = ?
For every mol MgCO3 you get 1 mol CO2; therefore ?mols MgCO3 = the same number of mols of CO2 produced. Now convert that to the conditions you want using PV = nRT.
P = 1 atm
V = solve for this in L.
n = from above
R = 0.08206 L*atm/mol*K
T = 350 C but convert to kelvin. K = 273 + C
Post your work if you get stuck.
What volume of carbon dioxide would be produced at 350˚C and
1.00 atm from the complete thermal decomposition of 1.00 kg of
magnesium carbonate, MgCO3? What is the density of carbon dioxide
at this temperature?
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2 answers