What volume of aluminum would be needed to balance a 1.00 cm^3 sample of copper on a 2 pan laboratory balance?

Answer 1

density Al * volume Al = density Cu * 1 cm^3

make sure density of Al is in g/cm^3

Answer 2

I literally have no idea what this means. Do I do both sides and divide one side? This is confusing.

Answer 3

You must look up the densities of Al and Cu
then your answer is
Volume of Al = (density CU/densityAL) *1 cm^3

Answer 4

Vol of Al = (8.9/2.7)*1
= 3.3 cm^3 of Al

Answer 5

Yay! I got the same answer, and I tried to figure it out before you answered. Good. That makes me happy. Thank you!