Ca(OH)2 + 2HBr ==> CaBr2 + 2H2O
mols Ca(OH)2 = M x L = ?
mols HBr = twice that (from the coefficients in the equation).
M HBr = mols HBr/L HBr. You know M and mols, solve for L HBr and convert to mL.
What volume of a 0.332 M hydrobromic acid solution is required to neutralize 29.6 mL of a 0.155 M calcium hydroxide solution ?
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