What volume of 3M hydrochloric acid will be required to react completely with 3.25 g of zinc
3 answers
Now
impatient much?
how many moles of Zn in 3.25g?
The equation will tell you how many moles of HCl will be used
3M HCl = 3 moles/liter, so divide the moles HCl by 3 to get liters
how many moles of Zn in 3.25g?
The equation will tell you how many moles of HCl will be used
3M HCl = 3 moles/liter, so divide the moles HCl by 3 to get liters
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = grams/atomic mass = 3.25/65.4 = about 0.0496 but you need to confirm the atomic mass Zn and give a more accurate answer.
Then from the equation, that many mols Zn will require twice that many mols of HCl.
Finally, mols = M HCl x L HCl. You know mols HCl and M HCl, solve for L HCl. Convert to mL if desired.
Post your work if you get stuck.
mols Zn = grams/atomic mass = 3.25/65.4 = about 0.0496 but you need to confirm the atomic mass Zn and give a more accurate answer.
Then from the equation, that many mols Zn will require twice that many mols of HCl.
Finally, mols = M HCl x L HCl. You know mols HCl and M HCl, solve for L HCl. Convert to mL if desired.
Post your work if you get stuck.
1 answer