Na2CO3 + 2HCl ==> 2NaCl + H2O + CO2
mols Na2CO3 = M x L = ?
Using the coefficients in the balanced equation, convert mols Na2CO3 to mols HCl.
Then M HCl = mols HCl/L HCl. YOu know M HCl and mols HCl, solve for L HCl.
What volume of 3.00M HCl in liters is needed to react completely (with nothing left over) with 0.750L of 0.400M Na2CO3?
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