What volume of .200M NaOH will be required to react completely with 32 mL of .15M HNO3

Answer 1

mL x M = mL x M

Answer 2

Convert mL to L
(32ml)(1L/1000mL) = 0.032L

(0.032L)(0.15M HNO3/1L) = 0.0048 moles HNO3

0.0048 mol = (.200M NaOH)(? L NaOH)

0.0048 / .200 = 0.024 L NaOH

0.024L (1000mL/1L) = 24ml NaOH

Good Luck with the rest of your Wiley Homework and hope this helps! :)

Answer 3

Oh, and by the way, you didn't post the equation for this question, so my answer above is assuming that there is an equal amount moles for NaOH and HNO3.

Answer 4

.018