M1V1=M2V2
17xV1=1.78X0.15
V1=0.01571 L
What volume of 17 M sulfuric acid must be used to prepare 0.15 L of 1.78 M H2SO4?
2 answers
You are diluting the acid 17/1.78 times, or 9.55 times
That means one part acid, and 8.55 parts water.
What is one part? .15L/9.55=15.7ml
so, 8.55 parts water is 15.7*8.55=134.2 ml water.
so add 15.7 ml of 17M acid to the water, stirring, (always acid to water).
That means one part acid, and 8.55 parts water.
What is one part? .15L/9.55=15.7ml
so, 8.55 parts water is 15.7*8.55=134.2 ml water.
so add 15.7 ml of 17M acid to the water, stirring, (always acid to water).
2 answers