what volume of 16 sulfuric acid must be used to prepare 1.5 L of a 0.10 M H2SO4 solution

6 answers

16 what? 16M?
c1v1 = c2v2
c = concn
v = volume
16M*v1 = 0.1*1.5M
Solve for v1.
Assuming that's 16M, find volume V when:

(16M) * V = (0.10M) * (1.5L)
9.4 mL of acid
Where is the work tho?
16 M*V=1.5 L * 0.10 M
V=(1.5 L * 0.10 M)/16M
=.00937L (9.375ml)
From dilution law
C1V1=C1V2
16M×V1=1.5M×0.10M
V1=0.00937L or 9.375mL