2HCl + Na2CO3 == 2NaCl + H2O + CO2
You have 3.65 g HCl. How many mols is that? That's mols = g/molar mass = 3.65/36.5 = 0.1 Look at the coefficients in the balanced equation. 0.1 mol HCl will need 1/2 that or 0.05 mols Na2CO3. How much is that in grams. mols Na2CO3 = grams Na2CO3/molar mass Na2CO3. You know molar mass and you know mols, solve for grams. Check my work.
What volume of 10 percentage (mass/volume) solution of Na2CO3 will be required to neutralise 100mL of HCl sution containing 3.65g of HCl.
1 answer
1 answer