what volume of .0250 M MgCl2 should be diluted to 250.0 mL to obtain a solution with [Cl]=.0135?
1 answer
mL1 x M1 = mL2 x M2 BUT since MgCl2 contains two atoms Cl2/molecule, make the M of MgCl2 just twice that listed; i.e., as 0.0250*2 = 0.050 M in chloride.