What Volume of 0.575M HCl will neutralize 4.22g of Mg(OH)2? I got the BRE of 2HCl + 1Mg(OH)2 ---> 1MgCl2 + H2O, what do i do from there?

Answer 1

2 H20, my bad

Answer 2

Convert 4.22 g Mg(OH)2 to mols. mols == grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols Mg(OH)2 to mols HCl.

M HCl = mols HCl/L HCl.; You know M and mols, solve for L HCl