Write the equation.
AgNO3 ==> AgCl (obviously 1 mol AgNO3 is need to form 1 mole AgCl).
0.657 g AgCl is how many moles? moles = g/molar mass = ??
moles AgCl = moles AgNO3.
Molarity = moles/L.
You know molarity and moles, solve for L.
What volume of 0.123 M AgNO3(aq) is needed to form 0.657 g of AgCl(s)?
0.564 mL.
18.6 mL.
37.2 mL.
1.77 L.
1 answer