What volume of 0.1000 M oxalic acid (a diprotic acid) would be required to completely neutralize 100.00 mL of 0.1000 M NaOH?

Answer 1

2NaOH + H2Ox ==> Na2Ox + 2H2O

mols NaOH = M x L = 0.1 x 0.1 = 0.01
mols H2Ox = 0.01 x (2 mols NaOH/1 mol H2Ox) = 0.01 x 2 = 0.02 mols NaOH
Then M H2Ox = mols H2Ox/L H2Ox. You know M and you know mols, solve for L. Convert to mL if desired.