What volume is produced when 10g of propyne is burnt in excess oxygen at S. T P
3 answers
Where is the answer
how many moles involved?
1 mole occupies 22.4L at STP
1 mole occupies 22.4L at STP
Propyne has the general formula of CnH2n-2 or specifically C3H4.
C3H4 + 4O2 --> 3CO2 + 2H2O
mols C3H4 = grams/molar mass = 10/40 = 0.25
Therefore, 0.25 mols C3H4 will produce 3*0.25 mols CO2 plus 2*0.25 mols H2O for a total of 0.75 + 0.50 = 1.25 mols of gas. Then each mol gas @ STP occupies 22.4 L.
C3H4 + 4O2 --> 3CO2 + 2H2O
mols C3H4 = grams/molar mass = 10/40 = 0.25
Therefore, 0.25 mols C3H4 will produce 3*0.25 mols CO2 plus 2*0.25 mols H2O for a total of 0.75 + 0.50 = 1.25 mols of gas. Then each mol gas @ STP occupies 22.4 L.
2 answers