what volume is occupied by 2.33 moles of an ideal gas at 0.953 atm and 44 C

Answer 1

To calculate the volume occupied by the gas, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in liters)
n = moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (in Kelvin)

First, we need to convert the temperature from Celsius to Kelvin:
44 C + 273 = 317 K

Now, we can plug in the values into the ideal gas law equation:
(0.953 atm) * V = (2.33 mol) * (0.0821 L.atm/mol.K) * (317 K)

0.953V = 60.86

V = 60.86 / 0.953
V = 63.93 L

Therefore, the volume occupied by 2.33 moles of an ideal gas at 0.953 atm and 44 C is 63.93 liters.