What volume (in mL) of a 0.125 MHNO3 solution is required to completely react with 26.1 mL of a 0.112 MNa2CO3 solution according to the following balanced chemical equation?

Question

What volume (in mL) of a 0.125 MHNO3 solution is required to completely react with 26.1 mL of a 0.112 MNa2CO3 solution according to the following balanced chemical equation?
Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

DrBob222 · Answer

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)
How many mols of Na2CO3 do you have? That's mols = M x L = 26.1 mL of a 0.112 MNa2CO3 soln or 0.112 M x 0.0261 L = ?
Now convert to mols HNO3. mols HNO3 will be 2 x mols Na2CO3, then
M = mols/L to convert to volume of HNO3 needed. M = mols/L. You know mols HNO3, you know M HNO3, solve for L HNO3 and convert to mL if desired. Post your work if you get stuck.