mL1 x M1 = mL2 x M2
Substitute.
mL1 x 0.355M = 19.9 mL x 15.0M
Solve for mL1
What volume (in milliliters) of 0.355 M aqueous ammonia, NH3, could be made from 19.9 mL of concentrated aqueous ammonia (15.0 M)?
(atomic masses: N = 14.01, H = 1.008)
2 answers
840.845
1 answer