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What volume (in milliliters) of 0.180 M NaOH should be added to a 0.135 L solution of 0.0230 M glycine hydrochloride (pKa1 = 2.350, pKa2 = 9.778) to adjust the pH to 2.73?

Plz help, I'm not sure how to answer the question!
Thank you!!

1 answer

the Henderson-Hasselbach equation:
2.73 = 2.35 - log( 0.0031/(0.18V))

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