What volume (in liters) of 0.96 M KOH solution should be added to a 0.090 L solution containing 9.9 g of glutamic acid hydrochloride (Glu, FW=183.59; pKa1=2.23, pKa2 =4.42, pKa3=9.95) to get to pH 10.20?

Answer 1

mols glutamic acid = 9.9/183.59 = estimated 0.05.
mols KOH needed = estimated 0.05
MKOH = mols KOH/L KOH or
L KOH = mols KOH/M KOH = estimated 0.05/0.96 = estimated 0.056 L or about 56 mL and that is one of the pKa values. Multiply that by 3 for total volume KOH required.