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What volume (in liters) is occupied by 3.85×10^22 nitrogen molecules at 105 C and 255 mmHg?

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Use PV = nRT.
n = (3.85E22/6.02E23)
P = 255/760 = ? atm
R = 0.0806 L*atm/mol*K
T = 273 + 105 = ?K
Solve for V in L.

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