What volume (in liters) is occupied by 0.01 moles of carbon monoxide, CO at 9 degrees C and 0.973 atm?
2 answers
PV = nRT
pv=nrt
hence, v=nrt/p
v=(0.01*0.082*282)10.972
v= 0.238L
hence, v=nrt/p
v=(0.01*0.082*282)10.972
v= 0.238L