What volume in leaders will 23.5 l of gas occupy if the pressure is changed from 76MMHG to 4091MHG

Answer 1

To find the new volume of gas, we can use the combined gas law equation:

(P1 * V1) / T1 = (P2 * V2) / T2

Where:
P1 = initial pressure (76 mmHg)
V1 = initial volume (23.5 L)
T1 = initial temperature (unchanged)
P2 = final pressure (4091 mmHg)
V2 = final volume (unknown)
T2 = final temperature (unchanged)

Solving for V2:
(76 * 23.5) = (4091 * V2)
1786 = 4091V2
V2 = 1786 / 4091
V2 = 0.4368 L

Therefore, 23.5 L of gas at 76 mmHg will occupy approximately 0.4368 L at 4091 mmHg.