What volume does a mixture of 14.2 g of He and 21.6 g of H2 occupy at 28 degrees celcius and 0.985 atm?

1 answer

PV=nRT n= moles of HE + moles H2

think about that. If you have studied Dalton's Law of Partial Pressures, it makes perfect sense...each gas has a partial pressure, and the sum of them is .985atm