First find East component of each
15 cos 45 - 30
Now find south component of each
15 sin 45 + 0
so
East = -19.4 or 19.4 West resultant
South = 10.6
tangent of angle south of West (quadrant 3) = 10.6/19.4 = .547
tan^-1 .547 = 28.7 degrees South of West
magnitude = sqrt (19.4^2+10.6^2)
What vector represents the displacement of a person who walks 15 km at 45 degrees south of east, then 30 km due west?
1 answer
2 answers