The given equation is:
2 sin(theta) cos(theta) + √3 cos(theta) = 0
Taking out a common factor of cos(theta), we get:
cos(theta)(2 sin(theta) + √3) = 0
Now, we find the values of theta that satisfy this equation:
1. cos(theta) = 0
This is true when theta is pi/2 or 3pi/2.
2. 2 sin(theta) + √3 = 0
sin(theta) = -√3/2
This is true when theta is 5pi/6 or 11pi/6.
Therefore, the values of theta that satisfy the equation are:
theta = pi/2, 3pi/2, 5pi/6, 11pi/6.
What values for theta (0 is less than or equal to theta which is less than or equal to 2pi) satisfy the equation?
2 sin theta cos theta + root three cos theta=0
1 answer
1 answer