What value of y would make the expression yb−6+7+2b−3b+1 equivalent to 5b+2 ?

Answer 1

To make the expression yb−6+7+2b−3b+1 equivalent to 5b+2, we need to combine like terms on both sides of the equation.

On the left side of the equation, we have:

yb−6+7+2b−3b+1

Combining like terms, we get:

(1y - 3b + 2b) + (7 - 6 + 1)

This simplifies to:

(1y - b) + 2

On the right side of the equation, we have:

5b+2

Now we can set the simplified expressions equal to each other:

(1y - b) + 2 = 5b + 2

To isolate the variable y, we can subtract 2 from both sides:

1y - b = 5b

Now, let's add b to both sides:

1y = 5b + b

Simplifying further, we get:

1y = 6b

So, the value of y that would make the expression yb−6+7+2b−3b+1 equivalent to 5b+2 is y = 6b.

Answer 2

it is wrong

Answer 3

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