2x-6=3x+1-x-7
Step 1: 2x-6=3x-6-x (how i got -6? 1-7 =-6)
step 2: 2x-6=2x-6 (how i got 2x? 3x-x=2x; there's an imaginary 1 in front of x)
step 3: Take ONLY the 6 on the left side of the equation, and add it to the 6 on the right side of the equation. So it will look like this,
2x-6+6=2x-6+6, therefore you'll get 2x=2x+0
step 2: Take the 2x on the right side of the equation and subtract it from the 2 in the left side of the equation. You'll get x=0 as your final answer. So your answer is 0.
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To check if 0 is the right answer. Plug in zero in every occurrence of x. So, 2(0)-6=3(0)+1-0-7. The left side of the equation will give u 0 and the right side of the equation will give you 0.
What value of x will make the equation below true?
2x-6=3x+1-x-7
3 answers
5b+15=30 we are a hard time with this
B = 3
5 x 3 = 15 +15 =30
5 x 3 = 15 +15 =30