To determine which value of \( x \) less than 65 can form a Pythagorean triple with the numbers 56 and 65, we can use the Pythagorean theorem. In a Pythagorean triple, the relationship is:
\[ a^2 + b^2 = c^2 \]
where \( c \) is the largest number. In this case, 65 is the largest number, so we have:
\[ x^2 + 56^2 = 65^2 \]
Calculating \( 56^2 \) and \( 65^2 \):
\[ 56^2 = 3136 \] \[ 65^2 = 4225 \]
Substituting these into the equation:
\[ x^2 + 3136 = 4225 \]
Now, we isolate \( x^2 \):
\[ x^2 = 4225 - 3136 \] \[ x^2 = 1089 \]
Now, take the square root of both sides:
\[ x = \sqrt{1089} = 33 \]
This value of \( x \) is less than 65. Therefore, the correct response is:
x equals 33.