What value makes the equation -5=4-(3x/4-3x) undefined?

Answer 1

To determine when the equation \(-5 = 4 - \left( \frac{3x}{4} - 3x \right)\) is undefined, we first need to simplify the expression inside the parentheses.

The expression \(\frac{3x}{4} - 3x\) can be simplified by first rewriting \(3x\) with a common denominator:

\[ 3x = \frac{12x}{4} \]

Now substituting this back into the expression, we have:

\[ \frac{3x}{4} - 3x = \frac{3x}{4} - \frac{12x}{4} = \frac{3x - 12x}{4} = \frac{-9x}{4} \]

Thus, we can rewrite the equation as:

\[ -5 = 4 - \left( \frac{-9x}{4} \right) \]

This simplifies to:

\[ -5 = 4 + \frac{9x}{4} \]

Now, let's isolate \(\frac{9x}{4}\):

\[ -5 - 4 = \frac{9x}{4} \]

\[ -9 = \frac{9x}{4} \]

Next, we can clear the fraction by multiplying both sides by 4:

\[ -9 \cdot 4 = 9x \]

\[ -36 = 9x \]

Now, we solve for \(x\):

\[ x = \frac{-36}{9} = -4 \]

Finally, we find that the equation becomes undefined when \(x = -4\).

So, the value that makes the equation undefined is:

\[ \boxed{-4} \]

Answer 2

Solve the equation for the variable k:30/k+1=4

Answer 3

To solve the equation

\[ \frac{30}{k} + 1 = 4, \]

we will start by isolating the term with \( k \) on one side of the equation.

First, subtract 1 from both sides:

\[ \frac{30}{k} = 4 - 1, \]

which simplifies to:

\[ \frac{30}{k} = 3. \]

Next, we can eliminate the fraction by multiplying both sides by \( k \):

\[ 30 = 3k. \]

Now, solve for \( k \) by dividing both sides by 3:

\[ k = \frac{30}{3} = 10. \]

Thus, the solution for \( k \) is

\[ \boxed{10}. \]

Answer 4

what is the value for the variable f in (17/3f-1)=1?

Answer 5

To solve the equation

\[ \frac{17}{3f - 1} = 1, \]

we'll start by eliminating the fraction. We can do this by multiplying both sides of the equation by \(3f - 1\):

\[ 17 = 1(3f - 1). \]

This simplifies to:

\[ 17 = 3f - 1. \]

Next, we'll isolate the term with \(f\). We can add 1 to both sides:

\[ 17 + 1 = 3f, \]

which simplifies to:

\[ 18 = 3f. \]

Now, to solve for \(f\), we'll divide both sides by 3:

\[ f = \frac{18}{3} = 6. \]

Thus, the value for the variable \(f\) is

\[ \boxed{6}. \]