what value is a solution to two of the equations p/2+4=10 2=10-6h 3y-16=20

Answer 1

To solve the equations, let's go through one by one:

1) p/2 + 4 = 10

Subtract 4 from both sides:

p/2 = 6

Multiply both sides by 2:

p = 12

So, the value of p is 12.

2) 2 = 10 - 6h

Subtract 10 from both sides:

-8 = -6h

Divide both sides by -6:

h = 8/6 = 4/3

So, the value of h is 4/3.

3) 3y - 16 = 20

Add 16 to both sides:

3y = 36

Divide both sides by 3:

y = 36/3 = 12

So, the value of y is 12.