The special right triangle that intersects the unit circle at (√2/2,√2/2) is a 45-45-90 triangle. In this triangle, both of the legs (opposite and adjacent) are equal in length, and the hypotenuse is √2 times the length of the legs.
Therefore, in this case, the legs are √2/2 in length, and the hypotenuse is √2 times that, i.e., √2 * √2/2 = √2/√2 = 1.
what type of special right triangle drawn inside the unit circle intersects the unit circle at (√2/2,√2/2)?
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1 answer