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Original Question
What type of number will result from multiplying −8–√ and 4/5 ?(1 point) Responses the number zero the number zero an irrationa...Asked by evergreen
What type of number will result from multiplying −8–√
and 45
?(1 point)
Responses
the number zero
the number zero
a rational number
a rational number
an integer
an integer
an irrational number
and 45
?(1 point)
Responses
the number zero
the number zero
a rational number
a rational number
an integer
an integer
an irrational number
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the type of number that results from multiplying \(-\sqrt{8}\) and \(45\), we first simplify the expression:
\[
-\sqrt{8} \times 45
\]
We can simplify \(\sqrt{8}\):
\[
\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2\sqrt{2}
\]
Now substituting this back into the multiplication:
\[
-\sqrt{8} = -2\sqrt{2}
\]
So now we have:
\[
-2\sqrt{2} \times 45 = -90\sqrt{2}
\]
Now we need to identify the type of the result, \(-90\sqrt{2}\).
- \(\sqrt{2}\) is an irrational number.
- Multiplying a rational number \(-90\) (which is an integer and thus also rational) by an irrational number \(\sqrt{2}\) results in an irrational number.
Thus, the multiplication:
\(-\sqrt{8} \times 45\) yields an **irrational number**.
The correct response is:
**an irrational number.**
\[
-\sqrt{8} \times 45
\]
We can simplify \(\sqrt{8}\):
\[
\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2\sqrt{2}
\]
Now substituting this back into the multiplication:
\[
-\sqrt{8} = -2\sqrt{2}
\]
So now we have:
\[
-2\sqrt{2} \times 45 = -90\sqrt{2}
\]
Now we need to identify the type of the result, \(-90\sqrt{2}\).
- \(\sqrt{2}\) is an irrational number.
- Multiplying a rational number \(-90\) (which is an integer and thus also rational) by an irrational number \(\sqrt{2}\) results in an irrational number.
Thus, the multiplication:
\(-\sqrt{8} \times 45\) yields an **irrational number**.
The correct response is:
**an irrational number.**
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