In the nuclear reaction you provided:
\[ \frac{35}{16} S \rightarrow \text{_____} + \frac{35}{17} Cl \]
we can deduce that sulfur-35 (S) is transforming into chlorine-35 (Cl). The atomic number increases from 16 (S) to 17 (Cl), which means that a particle with a negative charge must be emitted to account for the conservation of charge.
The particle that would be emitted in this type of reaction is a beta particle (β), which is an electron or positron emitted during beta decay. Specifically, since the atomic number increases, it would involve the emission of a beta minus particle (β-).
So, the reaction can be completed as follows:
\[ \frac{35}{16} S \rightarrow \frac{35}{17} Cl + \beta^- \]
Thus, the type of nuclear radiation given off in the reaction is beta radiation (β- decay).